Partari teneria roberta seneios para han recordiiooo sii
1-(-4)^2
1-(-4 times -4)
1-(16)
1-16
-15
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Answer:
See below ↓
Step-by-step explanation:
14.
- Between two lines m ║ n, the ∦ cuts through them forming two angles
- As it forms a line, the sum of the angles is 180°
- 3x + 47 + x + 7 = 180
- 4x + 54 = 180
- 4x = 126
- x = 126/4 = 63/2 = 31.5
15.
- Alternate exterior angles on a transversal are equal
- 5x = 2x + 78
- 3x = 78
- x = 26
Answer:
AC = 8√3 AC = 7.65
A = 43.17° AB = 16.8
B = 46.83° B = 27°
Step-by-step explanation:
FIRST TRIANGLE
by using pythagorus theorem:
Hypo² = Base² + height²
19² = 13² + AC²
AC² = 19² - 13²
AC² = 192
AC = √192
AC = 8√3
sinФ =base/hypo
sin A = 13/19
A = sin^-1 (13/19)
A = 43.17°
43.17°+ B + 90° =180 (sum of angles of triangle)
B = 180° - 133.17°
= 46.83°
<h3>SECOND TRIANGLE</h3>
TanФ = base/height
Tan 63° = 15 / AC
1.96 = 15/AC
AC = 15/1.96
AC = 7.65
AB² = AC² + BC²
AB² = 7.65² + 15²
AB² = 283.5
AB = √283.5
AB = 16.8
tan B = AC /BC
tanФ = 7.65/15
tanФ = 0.51
Ф = tan^-1(0.51)
B = 27°
