Let the first integer be 
. So, the next even number is 
Let's translate the formula: the square of the second is 
, twice the first is 
. So, the equation is
Expand the square to get
The solutions to this equations are
So, the possible consecutive even numbers are
The answer to this question should be D
Answer:
x-intercepts: (2, 0) and (−5, 0)
y-intercept: (0, −10)
Step-by-step explanation:
y = x^2 + 3x − 10
y-intercept when x = 0 so y = -10, so y-intercept : (0, -10))
x-intercept when y = 0 so
x^2 + 3x − 10 = 0
(x +5)(x - 2) = 0
x + 5 = 0; x = -5
x - 2 = 0; x = 2
So x-intercepts: (-5, 0) and (2,0)
Answer:
option D
(-1,-3) and (3,13)
Step-by-step explanation:
Given in the question two equations
y = 4x + 1
y = x² + 2x - 2
Equate both functions
4x + 1 = x² + 2x - 2
rearrange the x term and constant
-x² + 4x - 2x + 2 + 1 = 0
-x² + 2x + 3 = 0
factors
-x * 3x = -3x²
-x + 3x = 2x
-x² -x + 3x + 3 = 0
-x(x+1) +3(x+1) = 0
solve
(x+1)(3-x) = 0
x = -1
and
x = 3
Plug these values in equation to find y
x = -1
y = 4(-1)+ 1
y = -3
x = 3
y = 4(3)+ 1
y = 13
