Part A: monthly payment
Initial loan after downpayment,
P = 320000-20000= 300,000
Interest rate per month,
i = 0.06/12= 0.005
Number of periods,
n = 30*12= 360
Monthly payment,
A = P*(i*(1+i)^n)/((1+i)^n-1)
= 300000(0.005(1.005)^360)/(1.005^360-1)
= 1798.65
Part B: Equities
Equity after y years
E(y) = what they have paid after deduction of interest
= Future value of monthly payments - cumulated interest of net loan
= A((1+i)^y-1)/i - P((1+i)^y-1)
= 1798.65(1.005^y-1)/.005 - 300000(1.005^y-1)
= (1798.65/.005-300000)(1.005^y-1)
Equity E
for y = 5 years = 60 months
E(60) = (1798.65/.005-300000)(1.005^60-1) = 18846.17
for y = 10 years = 120 months
E(120) = (1798.65/.005-300000)(1.005^120-1) = 45036.91
y = 20 years = 240 months
E(240) = (1798.65/.005-300000)(1.005^240-1) = 132016.53
Check: equity after 30 years
y = 30 years = 360 months
E(360) = (1798.65/.005-300000)(1.005^360-1) = 300000.00 .... correct.
Based on the information given the percentage increase is 5%.
<h3>Percentage increase</h3>
Using this formula
Percentage increase=Population several years later-Population for year/Population for one year×100%
Let plug in the formula
Percentage increase=236,360-225,000/225,000×100
Percentage increase=5%
Inconclusion the percentage increase is 5%.
Learn more about percentage increase here:brainly.com/question/11360390
Answer:
![x\in [5.55,6.45]](https://tex.z-dn.net/?f=x%5Cin%20%5B5.55%2C6.45%5D)
Step-by-step explanation:
<u>Absolute Value Inequality</u>
Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.
Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.
The variation (unsigned) from the ideal width is:
The question requires that the variation is at most 0.45 cm. That poses the inequality:
That is the range of acceptable widths. Let's now solve the inequality.
To solve an inequality for an absolute value less than a positive number N, we write:
This is a double inequality than can be easily solved by adding 6 to all the sides.
Operating:
That is the solution in inequality form. Expressing in interval form:
![\boxed{x\in [5.55,6.45]}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%5Cin%20%5B5.55%2C6.45%5D%7D)
2000 + 16 = 2016
1008 * 2 = 2016
3000 - 984 = 2016
8064 / 4 = 2016
there are 4 different ways
Answer:
134
Step-by-step explanation:
first you have to add
