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ICE Princess25 [194]

2 years ago

10

Kenji is traveling in Europe and renting a car. He is used to thinking of gasoline amounts in gallons, but in Europe it is sold

in liters. After filling the gas tank, he notices it took 39 L of gas. How many gallons is that?

1 answer:

finlep [7]2 years ago

7 0

10.3 gallons

Good luck!!!!!

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Jennifer spent $42 on a magazine and 7 candy bars. The magazine cost $7, then how much was each candy bar

Genrish500 [490]

$5. You subtract the $7 from the $42 since that was the magazine then you divide that(35) by 7 since that is the amount of candy bars that were bought. That’ll give you the answer of $5 for each candy bar.

3 0

2 years ago

F(7) if f(x)=-3x-2

Paul [167]

Answer:

f(7) = -23

Step-by-step explanation:

f(x) = -3x - 2

f(7) = -3(7) - 2

f(7) = -21 - 2 = -23

4 0

2 years ago

Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack

brilliants [131]

Answer:

0.54 ounces in each tube

Step-by-step explanation:

Add the amount she used so we can add it in. 1.35+0.27= 1.62. Then divide it by the number of tube and since it was a 3 pack you divide it by 3. 1.62/3=0.54 so there is 0.54 ounces in each tube.

5 0

2 years ago

Read 2 more answers

X^2 -9X = 0. Factor and use the Zero property to solve

Veseljchak [2.6K]

The first step of factoring is to try to factor out a common factor.
The terms x^2 and -9x have the factor x in common.
Factor out x from both terms.

x^2 - 9x = 0

x(x - 9) = 0

Now you have a product of fully factored terms equaling zero, so you can apply the zero product property to solve.

x = 0 or x - 9 = 0

x = 0 or x = 9

Answer: x = 0 or x = 9

5 0

2 years ago

What is the completely factored form of f(x)=x^3+4x^2+7x+6?

Reptile [31]

we are given

$f(x)=x^3+4x^2+7x+6$

We will use rational root theorem to find factors

We can see that

Leading coefficient =1

constant term is 6

so, we will find all possible factors of 6

$6=\pm 1,\pm 2,\pm 3,\pm 6$

now, we will check each terms

At x=-2:

We can use synthetic division

we get

$f(-2)=0$

so, x+2 will be factor

and we can write our expression from synthetic division as

$f(x)=x^3+4x^2+7x+6=(x+2)(x^2+2x+3)$

$f(x)=(x+2)(x^2+2x+3)$

now, we can find factor of remaining terms

$x^2+2x+3=0$

we can use quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

we can compare our equation with quadratic equation

we get

$a=1,b=2,c=3$

now, we can plug these values

$x=\frac{-2+\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}$

$x=-1+\sqrt{2}i$

$x=\frac{-2-\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}$

$x=-1-\sqrt{2}i$

so, we get

$x=-1+\sqrt{2}i,\:x=-1-\sqrt{2}i$

so, we can write factor as

$x^2+2x+3=(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))$

so, we get completely factored form as

$f(x)=(x+2)(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))$ ...............Answer

7 0

2 years ago