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nordsb [41]
4 years ago
11

If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a

poset that is a total ordering?
I. A- (1, 4, 16, 64)
II. A- (1.2,3, 4, 6, 12)
III. A 1,2,3, 4, 6, 12, 18, 24)
IV. A+{1 , 2, 3, 6, 12)
Mathematics
1 answer:
Marrrta [24]4 years ago
5 0

Answer:

IV. A+{1, 2, 3, 6, 12}

Step-by-step explanation:

The set of natural numbers form a poset number under relation of > or =. The discrete variables are used to form a poset. The symbols for divisibility in poset form are when an integer is divided by the variable without integer. The correct answer is therefore 4th option.

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B

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7 0
4 years ago
If the third term of an A.p. is 5 and the seventh term is 9 find the 17th number​
Schach [20]

Here,

Third term (a) = 5

Seventh term (b) = 9

17th number = ?

Now,

T3 = a + 2d

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d = (5 - a)/2 ------ 1.

T7 = a + 6d

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d = (9 - a)/6 ------- 2.

Combining eq (1) and (2)

or, (5 - a)/2 = (9 - a)/6

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or, 30 - 6a = 18 - 2a

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or, d = (5 - 3)/2

or, d = 2/2

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Then,

T17 = a + 16d

= 3 + 16

= 19

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I hope you understand...

This is Right answer...

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7 0
3 years ago
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Step-by-step explanation:

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4 years ago
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KATRIN_1 [288]

Answer:

The answer to your question is below

Step-by-step explanation:

Domain of a function is the complete set of possible values of "x".

In a radical function, domain must be ≥ 0.

Exercise

                      f(x) =  \sqrt{x + 4}

Then

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8 0
3 years ago
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