B
rearrange into standard form : ax² + bx + c = 0 (a≠ 0)
2x² - 3x - 2 = 0
(x - 2)(2x + 1) = 0 ( equate each factor to zero and solve for x )
x - 2 = 0 ⇒ x = 2
2x + 1 = 0 ⇒ x = - 0.5
Here,
Third term (a) = 5
Seventh term (b) = 9
17th number = ?
Now,
T3 = a + 2d
5 = a + 2d
d = (5 - a)/2 ------ 1.
T7 = a + 6d
9 = a + 6d
d = (9 - a)/6 ------- 2.
Combining eq (1) and (2)
or, (5 - a)/2 = (9 - a)/6
or, 6 (5 - a) = 2 (9 -a)
or, 30 - 6a = 18 - 2a
or, 12 = 4a
◆ a = 3
putting the value of a in eq (1)
or, d = (5 - 3)/2
or, d = 2/2
◆ d = 1
Then,
T17 = a + 16d
= 3 + 16
= 19
◆ T17 = 19
I hope you understand...
This is Right answer...
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I don’t know what it is that’s confusing /72873)472
Answer:
The answer to your question is below
Step-by-step explanation:
Domain of a function is the complete set of possible values of "x".
In a radical function, domain must be ≥ 0.
Exercise
f(x) = 
Then
x + 4 ≥ 0
x ≥ -4
Domain is x ≥ -4 or [-4 , ∞)