MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
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(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB
He makes 1,172.50. you find this by dividing 2345 by 2 (since that’s his BI weekly salary which means every 2 weeks he gets paid) when you divide by 2 you get 1,172.50
Where is the picture ?? I don’t understand ok
<h2>
Answer</h2>
The answer to this question is 0.9
<h2>
Explanation</h2>
We know that
sequre of 9 is equal to 81 as 
Then sequre of 0.9 will be
So,
b = 
b = 
Exponent and square root cancel out each other
So, the answer is 0.9.
