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Tom [10]
3 years ago
5

A survey is being conducted in a county where 62% of the voters are Democrats and 38% are Republican. (a) What is the probabilit

y that two independently surveyed voters would both be Democrats?
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either the voter is a Democrat, or he is not. The probability of the voter being a Democrat is independent of other voters. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

62% of the voters are Democrats

This means that p = 0.62

(a) What is the probability that two independently surveyed voters would both be Democrats?

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.62)^{2}.(0.38)^{0} = 0.3844

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

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