Answer:
8*5^n-1 / 2^n-1 = n
This is the function for your sequence
Answer:
22
Step-by-step explanation:
Generate the terms of sequence T using the nth term formula n² - 3
a₁ = 1² - 3 = 1 - 3 = - 2
a₂ = 2² - 3 = 4 - 3 = 1
a₃ = 3² - 3 = 9 - 3 = 6
a₄ = 4² - 3 = 16 - 3 = 13
a₅ = 5² - 3 = 25 - 3 = 22
22 is common to sequence S and T
Answer:
53.2 kg
Step-by-step explanation:
Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...
((E-5.2) + E + (E/2))/3 = 42.6
2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify
2.5E = 133 . . . . . . . . . . . . . . . . add 5.2
E = 133/2.5 = 53.2 . . . . kg
Esther's weight is 53.2 kg.
Answer: 4/9
Step-by-step explanation:
The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)
Pt = Po+Pi
Since the total number of birds in the right pond is 10 after the addition of one by john
Po= 4/10
Pi= the of john adding a duck × the probability of annie picking the added bird
Pi= 4/9 × 1/10
Pi = 4/90
Pt= 4/10 + 4/90
Pt = (36+4)/90
Pt=40/90
Pt= 4/9
(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)
Thanks.
<h3>
Answer: x = 7</h3>
Explanation:
Segment addition postulate
CD+DE = CE
this basically is the idea of gluing smaller pieces together to get a larger structure. We can go in reverse to break up a large item into smaller bits. This is assuming there is no leftovers, overlaps, or parts wasted/lost.
CD = 9
DE = 3x+6
CE = 36
----
CD+DE = CE
9+3x+6 = 36
3x+15 = 36
3x = 36-15
3x = 21
x = 21/3
x = 7
-----
If x = 7, then
DE = 3x+6 = 3*7+6 = 21+6 = 27
and
CD+DE = 9+27 = 36 = CE
confirming our answer
