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3 years ago

If f(x) = 4^x - 8 and g(x) = 5x + 6, find (f - g)(x)

Mathematics

2 answers:

olganol [36]3 years ago

6 0

Answer:

$4^x-5x-14$

Step-by-step explanation:

$f-g=(4^x-8)-(5x+6)=4^x-8-5x-6=4^x-5x-14$

Yuri [45]3 years ago

3 0

Answer:

The value of $(f-g)(x)=4^x-5x-14$

Step-by-step explanation:

Given : If $f(x) = 4^x-8$ and $g(x)=5x+6$

To find : The value of $(f - g)(x)$ ?

Solution :

$f(x) = 4^x-8$

$g(x)=5x+6$

We can write, $(f-g)(x)=f(x)-g(x)$

Substitute the value of f(x) and g(x)

$(f-g)(x)=4^x-8-(5x+6)$

$(f-g)(x)=4^x-8-5x-6$

$(f-g)(x)=4^x-5x-14$

Therefore, The value of $(f-g)(x)=4^x-5x-14$

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In a retail setting, payroll is often based on projected sales. If your payroll budget is 6% of projected sales of $3500.00 and

Bad White [126]

The maximum number of hours that can be allocated in a day is 21

Data given;

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This is the process of finding a fraction of a value multiplied by 100.

Let's find the actual figure allocated to employee pay.

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Now we know the actual amount allocated to employee pay and it is $210.

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2 years ago

3. Bob the Builder wants to earn an annual rate of 10% on his investments,

mamaluj [8]

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

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In this question:

Rate of 10%, so I = 0.1.

9 months, so $t = \frac{9}{12} = 0.75$

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We have to find P for which T = 3000. So

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$3000 = E + P$

$E = 3000 - P$

Then

$E = P*I*t$

$3000 - P = P*0.1*0.75$

$1.075P = 3000$

$P = \frac{3000}{1.075}$

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He should pay $2,790.7.

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3 years ago

An airplane is 32,000 feet above the ground begins descending at a rate 2,500

grandymaker [24]

Answer:

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Step-by-step explanation:

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3 years ago

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Hello I am really struggling on this test, can someone please help me and I will help you

olganol [36]

Answer:

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3 years ago

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Savatey [412]

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