Question

Simplify (-2x^4y^-3)^4

Answer 1

Answer:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$

Step-by-step explanation:

We want to simplify:

$( - 2 {x}^{4} {y}^{ - 3} )^{4}$

We need to apply the exponential property for products of powers.

Recall that:

$( {a}^{m} \times {a}^{n} )^{p} = {a}^{mp} \times {a}^{np}$

We apply this rule to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = ( { - 2)}^{4} x \times {x}^{16} \times {y}^{ - 12}$

This simplifies to:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = 16 {x}^{16} \times {y}^{ - 12}$

We rewrite as positive index to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$