The eggs of the order odonata undergo development called what metamorphosis

( THIS IS SCIENCE WORK ) HELP ASAP PLS I NEED HELP NO LINKS PLS

kolezko [41]

Answer:

Explanation:

Why is the taiga (boreal forest) considered "the driest moist biome" ?

Question 4 options:

Because it rains as little as the temperate rain forest, but retains most of its water throughout the year because of the cool temperatures.

Because it rains more than a tropical rainforest, but retains most of its water throughout the year because of the cool temperatures.

Because it rains as little as a desert, but retains most of its water throughout the year because of the cool temperatures.

Because it rains less than a desert, but retains most of its water throughout the year because of the cool temperatures.

8 0

3 years ago

Which term best describes the process that increases the quantity of cells

Romashka-Z-Leto [24]

Answer:

Cell Divide

Explanation:

When cells increase in numbers they go through a special process. This process makes them divide into to two exact copies of each other.

8 0

3 years ago

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ANSWER AND I WILL GIVE BRAINLIEST AND POINTS!

ehidna [41]

Answer:

A DNA marker

Explanation:

also known as a size standard or a DNA ladder) is loaded into the first well of the gel. The fragments in the marker are of a known length so can be used to help approximate the size of the fragments in the samples.

8 0

2 years ago

Animals conduct certain behaviors is mating. some practice in which one male breeds with only one female and others practice ,in

lbvjy [14]

The answer is C.

Monogamy: when one male breeds with only one female for life.
polygyny: where one male mates with multiple females.

8 0

2 years ago

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Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some

Sphinxa [80]

Answer and Explanation:

The number of observed individuals:

AA 42

AG 24

GG 21

Total number of individuals, N= 87 = 42 + 24 + 21

Allelic frequencies:

f(p) = (2 x AA + AG)/ 2 x N

f (p)= (2 x 42 + 24) /2 x 87

f (p) = (84 + 24) / 174

f (p)= 108 / 174

f (p) = 0.62

f (q) = (2 x GG + AG)/2 x N

f (q) = (2 x 21 + 24 )/2 x 87

f (q) = (42 + 24)/ 174

f (q) = 66/174

f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

The expected genotypic frequency:

F (AA)= 0.62 ² = 0.3844

F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712

F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

The number of expected individuals:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

Total number of expected individuals = 33.44 + 40.99 + 12.563 = 87

Chi square= sum (O-E)²/E

AA= (O-E)² /E

AA=(42 - 33.44) ² / 33.44

AA= 2.2

AB= (O-E)² /E

AB= (24 - 40.99)²/ 40.99

AB=7.04

BB=(O-E)² /E

BB= (21-12.563)²/12.563

BB= 5.66

Chi square= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

Degrees of freedom = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

5 0

3 years ago