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3 years ago

How to find the intersection of a circle and parabola?

1 answer:

8 0

Use the substitution method to solve for the system of equations:

Circle: (x-h)² + (y-k)² = r²
Parabola: y = a(x-h)² + k or x = a(y-k)² + h

(I am using the "y=" parabola for this example)

Substitute a(x-h)² + k for y into the circle equation and solve for x:
(x-h)² + [(a(x-h)² + k)² - k]² = r²

Then, substitute that x value into the parabola equation to solve for y.

Hope this makes sense!

You might be interested in

Find the center and radius of the circle whose equation is x2 + y2 - 6x-2y+4= 0

marin [14]

Answer:

The center of the circle = (3, 1)

The radius of a circle is given as r = √6

Step-by-step explanation:

The equation of a circle is given as:

( x - a)² + (y - b)² = r²

where ( a , b) = center of the circle

r = radius of the the circle

In the question above, we are given the equation of a circle as

x² + y² - 6x - 2y + 4= 0

In order to find the center and radius of this circle we would use completing the square method to solve it

Step 1

Collect the like terms

x² - 6x + y² - 2y + 4= 0

Step 2

Complete the square for both x and y

x² - 6x + (-6/2)² + y² - 2y + (-2/2)² = - 4 +(- 6/2)² + (-2/2)²

x² - 6x + (-3)² + y² - 2y + (-1)² = -4 + (3)² + (1)²

x² - 6x + 9 + y² - 2y + 1 = -4 + 9 + 1

(x² - 6x + 9) + (y² - 2y + 1 )= -4 + 9 + 1

(x² - 3x - 3x +9) + ( y² - y - y +1) = 6

x(x - 3) -3( x - 3) + y( y - 1) - 1( y - 1) = 6

(x - 3) (x -3) +(y - 1) ( y - 1) = 6

(x - 3)²(y - 1)² = 6

Since,

The equation of a circle is given as:

( x - a)² + (y - b)² = r²

where ( a , b) = center of the circle

r = radius of the the circle

The equation of the the circle for the above question is calculated as:

(x - 3)²(y - 1)² = 6

where ( a , b) = center of the circle = (3, 1)

r = radius of the the circle

r² = 6

r = √6

8 0

3 years ago

the debate team is showing a video of their recent debate. the first showing begins at 3:15 P.M. The second showing is scheduled

JulijaS [17]

The video will end at 4.20 PM (4.50 - 30 mins). So it starts at 3.15 PM and ends at 4.20 PM. So it is 1 hour and 5 minutes.

4 0

3 years ago

Read 2 more answers

Find the area of the shaded region.

jolli1 [7]

Answer:

15x-36

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

8-35. Use your knowledge of polygons to answer the questions below, if possible.

Nataliya [291]

Answer:

(a)I. 13 Sides II. 7 Sides

(b) 4 Sides, Square

(c)x=52 degrees

(d)x=107 degrees

(e)1620 degrees

Step-by-step explanation:

(a)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

I. If the Interior angle is $1980^0$

Then:

$(n-2)180^0=1980^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=11\\$Add 2 to both sides of the equation\\n-2+2=11+2\\n=13$

The polygon has 13 sides.

II. If the Interior angle is $900^0$

Then:

$(n-2)180^0=900^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=5\\$Add 2 to both sides of the equation\\n-2+2=5+2\\n=7$

The polygon has 7 sides.

(b)The sum of the exterior angle of a polygon is 360 degrees,

Each exterior angle of a n-sided regular polygon is: $\frac{360^0}{n}$

If the exterior angle of a regular polygon is 90°

Then:

$90\°=\frac{360^0}{n}\\ 90n=360\\n=4$

The regular polygon has 4 sides and it is called a Square.

(c)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

Each Interior angle of a regular n-sided polygon is: $\frac{(n-2)180^0}{n}$

For a pentagon, n=5

Then:

$\frac{(5-2)180^0}{5}=2x+4\\108=2x+4\\108-4=2x\\104=2x\\x=52^0$

(d)The sum of the exterior angle of a polygon is 360 degrees.

If four of the exterior angles of a pentagon are 57, 74, 56, and 66.

Let the fifth angle=x

Then:

$57+74+56+66+x=360^0\\253+x=360\\x=107^0$

(e)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

In an 11-gon., n=11

Therefore, the sum of the interior angle=(11-2)180= $1620^0$

The sum of the interior angle does not change either in a regular or irregular polygon.

3 0

3 years ago

A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght

expeople1 [14]

Answer:

$8.5m^{2}+ m -5$

Step-by-step explanation:

Since perimeter, $P=19m^{2}+ 2m -10$ and we know that P=2(l+w) then $P=2(l+m^{2})=2l+2m^{2}$

The length will be $2l=19m^{2}+ 2m -10-2m^{2}=17m^{2}+ 2m -10$

Now $l=8.5m^{2}+ m -5$

6 0

3 years ago