The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
<h3 />
The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
brainly.com/question/4289712
#SPJ1
<h2><u>Problem Solving</u>:-</h2>
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.
<h2><u>Solution</u>:-</h2>
Since the distance d varies directly as the time t, then d = kt.
Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.
<h2><u>Answer</u>:-</h2>
- Therefore, the constant of variation is 10.
Answer:
$72
Step-by-step explanation:
I did 36 x 2. I did not subtract the -6 for the prize money because it says not to.
The expression (x^22) (x^7)^3 is equivalent to x^p what is the value of p
Answer:
8/17 i hope this helps! :)
Step-by-step explanation:
measure of angle k = 8/17 = 28.072 degrees
measure of angle m = 15/8 = 61.928 degrees
