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DiKsa [7]
3 years ago
13

What is the vertex of a parabola defined by the equation x = 5y2?

Mathematics
1 answer:
QveST [7]3 years ago
3 0

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

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Step-by-step explanation:


6 0
3 years ago
What is the product? One-eighth times three-elevenths 3 over 88 1 over 22 4 over 19 35 over 88
kipiarov [429]

Answer:

\frac{3}{88}

Step-by-step explanation:

Given

One-eighth times three-elevenths

Required

Solve

One-eighth means 1/8

Three-elevenths means 3/11

So, mathematically; the above expression is represented as thus:

\frac{1}{8} * \frac{3}{11}

To solve this, we simply multiply the numerator and the denominator together.

After multiplying these together, the next is to check if the resulting can be simplified

If yes,we simplify it and if otherwise, we live it like that.

So,

\frac{1}{8} * \frac{3}{11}

=\frac{1 * 3}{8 * 11}

= \frac{3}{88}

At this point, the fraction can't be simplified any further.

Hence,

\frac{1}{8} * \frac{3}{11} = \frac{3}{88}

3 0
3 years ago
20 Points + Brainliest for the answer and Explanation!!!
Vlad1618 [11]

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

8 0
3 years ago
Can someone Please help me ???<br> If you can help me ill give you 20 points and brainliest :)
Phoenix [80]

First, classify each line segments of triangle that are the same in both triangles.

RS = XU

RT = XW

ST = WU

Second, divide to find the scale ratio.

7.5/3 = 2.5

16/6.4 = 2.5

15/6 = 2.5

Since the scale ratios are identical, the triangles are similar.

Therefore, the answer is [ Yes, the sides are in the ratio 2:5 ]

Best of Luck!

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