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2 years ago

7

The sum of 3 times the value of x and 2 is equal to 4 less than 5 times the value x. Which equation can be used to find the valu

e of x?

2 answers:

weeeeeb [17]2 years ago

7 0

Answer:

Write the written problem into an equation to get:

3x +2 = 5x -4

To solve:

Add 4 to each side:

3x+6 = 5x

Subtract 3x from each side:

2x = 6

Divide both sides by 2:

x = 6/2

x = 3

You didn't list the options so it could like like any of the equations I show above.

Step-by-step explanation:

lol ok

Komok [63]2 years ago

6 0

Answer:

Write the written problem into an equation to get:

3x +2 = 5x -4

To solve:

Add 4 to each side:

3x+6 = 5x

Subtract 3x from each side:

2x = 6

Divide both sides by 2:

x = 6/2

x = 3

Step-by-step explanation:

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Debbie solved the linear equation 3(x + 4) − 2 = 16 as follows: between what lines did she make an error? line 1 and line 2 line

Drupady [299]

The question is not clear because the Debbie solution lines are not visible. Nevertheless,
The correct solution for this linear equation is the following:
<span>3(x + 4) − 2 = 16
</span><span>3(x + 4) = 16 + 2
</span><span>3(x + 4) = 18
</span>(x + 4) = 18/3
(x + 4) = 6
x = 6 - 4
x = 2

3 0

3 years ago

Point B is on line segment AC. If AB = x + 6, BC = x + 8 and AC = 10, then find the value of x.

kumpel [21]

Step-by-step explanation:

this simply means that the sum of both short segments must be the same as the length of the whole line.

so,

x + 6 + x + 8 = 10

2x + 14 = 10

x + 7 = 5

x = 5 - 7 = -2

7 0

2 years ago

Problem-solving Practice

kotykmax [81]

First, what's 3 to the power of 8?
Then what's 3 to the power of 10

Now subtract them by each other for your answer

6 0

2 years ago

Read 2 more answers

Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form

Verizon [17]

<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is $\pm \frac{p}{q}$ , with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

$\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84$

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

$f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}$

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

3 | 1 - 10 + 25 - 40 + 84
_________________

Firstly, drop the 1:

3 | 1 - 10 + 25 - 40 + 84
↓
_________________
1

Next, multiply 3 and 1, then add the product with -10:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3
_________________
1 - 7

Next, multiply 3 and -7, then add the product with 25:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21
_________________
1 - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12
_________________
1 - 7 + 4 - 28

Lastly, multiply -28 and 3, then add the product with 84:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12 - 84
_________________
1 - 7 + 4 - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format $ax^3+bx^2+cx+d$ . In this case, our quotient is $x^3-7x^2+4x-28$ .

So right now, our equation looks like this:

$f(x)=(x-3)(x^3-7x^2+4x-28)$

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

$f(x)=(x-3)(x^2(x-7)+4(x-7))$

Now it can be rewritten as:

$f(x)=(x-3)(x^2+4)(x-7)$

<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

$f(x)=(x-3)(x^2+4)(x-7)$

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