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ehidna [41]
3 years ago
15

True r false? A circle could be circumscribed about the quadrilateral below?

Mathematics
2 answers:
galina1969 [7]3 years ago
6 0

True. The center is visible

nataly862011 [7]3 years ago
6 0

Answer:

I would say its true

Step-by-step explanation:

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Exact value: 9mm<br> approx value: 11mm
defon

Answer:

Your quality and RELIABLE 9mm pistol will typically run you $450–800 new with the large majority falling in the $500–600 range. Guns below that generally aren't worth purchasing outside of fun times. Guns above that generally have “extra” features that drive up the cost.

Step-by-step explanation:

8 0
2 years ago
Consider the sequence {an}={3n+13n−3n3n+1}. Graph this sequence and use your graph to help you answer the following questions.
Fantom [35]

Part 1: You can simplify a_n to

\dfrac{3n+1}{3n}-\dfrac{3n}{3n+1} = \dfrac1{3n}+\dfrac1{3n+1}

Presumably, the sequence starts at <em>n</em> = 1. It's easy to see that the sequence is strictly decreasing, since larger values of <em>n</em> make either fraction smaller.

(a) So, the sequence is bounded above by its first value,

|a_n| \le a_1 = \dfrac13+\dfrac14 = \boxed{\dfrac7{12}}

(b) And because both fractions in a_n converge to 0, while remaining positive for any natural number <em>n</em>, the sequence is bounded below by 0,

|a_n| \ge \boxed{0}

(c) Finally, a_n is bounded above and below, so it is a bounded sequence.

Part 2: Yes, a_n is monotonic and strictly decreasing.

Part 3:

(a) I assume the choices are between convergent and divergent. Any monotonic and bounded sequence is convergent.

(b) Since a_n is decreasing and bounded below by 0, its limit as <em>n</em> goes to infinity is 0.

Part 4:

(a) We have

\displaystyle \lim_{n\to\infty} \frac{10n^2+1}{n^2+n} = \lim_{n\to\infty}10+\frac1{n^2}}{1+\frac1n} = 10

and the (-1)ⁿ makes this limit alternate between -10 and 10. So the sequence is bounded but clearly not monotonic, and hence divergent.

(b) Taking the limit gives

\displaystyle\lim_{n\to\infty}\frac{10n^3+1}{n^2+n} = \lim_{n\to\infty}\frac{10+\frac1{n^3}}{\frac1n+\frac1{n^2}} = \infty

so the sequence is unbounded and divergent. It should also be easy to see or establish that the sequence is strictly increasing and thus monotonic.

For the next three, I'm guessing the options here are something to the effect of "does", "may", or "does not".

(c) may : the sequence in (a) demonstrates that a bounded sequence need not converge

(d) does not : a monotonic sequence has to be bounded in order to converge, otherwise it grows to ± infinity.

(e) does : this is true and is known as the monotone convergence theorem.

5 0
3 years ago
Find the unknown digit to make each statement true <br> 3.59 &gt; 3.5 1 &gt;3.572
Softa [21]

We are given statement 3.59 > 3.5__1 >3.572.

We have a blank space in between 5 and 1 in the middle number given.

Given statement ccan be read as :

3.59 is greater than 3.5__1 is greater than 3.572.

So, we need to check a number that is less than 3.59 but less than 3.572.

The hundredth place of 3.59 number is 9 and

hundredth place of 3.572 number is 7.

So, we need to find a number between 7 and 9.

8 is the number in between 7 and 9.

So, the known digit can be replaced by 8 to make the statement true.

And final statement is 3.59 > 3.581 >3.572.

6 0
3 years ago
Read 2 more answers
Alvin's age is two times Elga's age. The sum of their ages is 84 . What is Elga's age?
son4ous [18]
Alvin's age + Elga's age = 84
2R + R                             = 84 
3 R                                   = 84
3/ 3 R = 84/ 3 
R = 28 
Elga's age is 28 
6 0
3 years ago
How do I find the range of a function (no links)
Anna11 [10]
D is your answer because the bar is 4 and you must have an equal amount of plates on each side so it cannot be B. It goes up by 40 because of 2 plates on each side of the bar
6 0
3 years ago
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