Answer : 12 square root 5
4 square root 45
4 square root 9 times square root 5
4 time 3 square root 5
12 square root 5
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:Something Like
Step-by-step explanation:
Thanks!
Answer:
<h2>
</h2>
Step-by-step explanation:
- 2(5y - 1) - y = - 4(y - 3)
Expand the terms in the bracket
That's
-10y + 2 - y = - 4y + 12
Group like terms
Send the constants to the right side of the equation and those with variables to the left side
That's
- 10y - y + 4y = 12 - 2
- 7y = 10
Divide both sides by - 7
We have the final answer as
<h3>
</h3>
Hope this helps you
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