What is the formula for compound interest?

Helppppppppppppppppppppppp

Vikentia [17]

Step-by-step explanation:

area of trapezoid=(a+b)×h divided by 2

=(9+19)×4 divided by2

=28×4 divided by2

=112 divided by 2

=56m square

6 0

2 years ago

The actual length of a in the triangle shown is 10 cm. Use the scale drawing of the triangle to find the actual length of side b

geniusboy [140]

Umm Do you have A Picture For It Cause If You Don't Then I Can't Answer It

6 0

3 years ago

PLSSSS ASAPPP!!!!!!!!!!

konstantin123 [22]

The answer is 13, i got this by using the pythagorean theorem. a^2 + b^2 = c^2. in this case it would be 84^2 + b^2 = 85^2. then that would turn into 7056 + b^2 = 7225, subtract both sides by 7056 to get b^2 = 169, then square 169 to get 13 :)

3 0

3 years ago

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Which is the equation in the slope-intercept form of the line that contains points E & F ?

sesenic [268]

Answer:

y = 4x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = E(4, 4) and (x₂, y₂ ) = F(2, - 4)

m = $\frac{-4-4}{2-4}$ = $\frac{-8}{-2}$ = 4 , then

y = 4x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 4), then

4 = 16 + c ⇒ c = 4 - 16 = - 12

y = 4x - 12 ← equation of line

3 0

3 years ago

Read 2 more answers

Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$