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3 years ago

5

The sum of 6 consecutive even numbers is 126. What is the fourth number in this sequence?

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

The 6 numbers are: 16, 18, 20, 22, 24, and 26 so the answer would be 22.

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Would you solve the equation 0.25x + 7 = 1/3x – 8 <br> using fractions or decimals? Explain please.

mamaluj [8]

Answer:

$x = 180$

Step-by-step explanation:

Solve the value of $x$ :

$0.25x + 7 = \frac{1}{3}x - 8$

-Combine $\frac{1}{3}x$ and $0.25x$ by subtracting $0.25x$ by $\frac{1}{3}x$ :

$0.25x - \frac{1}{3}x + 7 = \frac{1}{3}x - \frac{1}{3}x - 8$

$-\frac{1}{12}x + 7 = -8$

-Subtract $7$ on both sides:

$-\frac{1}{12}x + 7 - 7 = -8 - 7$

$-\frac{1}{12}x = -15$

-Multiply both sides by $-12$ , the reciprocal of $-\frac{1}{12}$ :

$\frac{-\frac{1}{12}x}{-\frac{1}{12}} = \frac{-15}{-\frac{1}{12}}$

$x = -15 (-12)$

$x = 180$

Therefore, the value of $x$ is $180$ .

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3 years ago

If one million people have equal chances of being called by telephone from a broadcasting show, then the probability of one part

zhenek [66]

1 /million is the chance
1/1,000,000 or in decimals 0.000001 is the chance

7 0

3 years ago

At the beginning of the fall, the water level of a lake is 12

spayn [35]

x = normal water level

x - 12 - 13 = x - 25

so it is 25 feet below the normal water level

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3 years ago

Consider a tree T storing 100,000 entries. What is the worst-case height of T in the following cases?

Darina [25.2K]

Answer:

Step-by-step explanation:

a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.

b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.

c.) A red-black tree with 100,000 entries is 2 log 100, 000

d.) The worst-case height of T is 100,000.

e.) A binary search tree storing such a set would have a worst-case height of 100,000.

6 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the st

Zina [86]

Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:

$Sin\theta = \frac{-15}{17}$

$Tan\theta = \frac{15}{8}$

Step-by-step explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that

$cos(\theta) = \frac{Adj}{Hyp}$

Where Adj and Hyp represent Adjacent and Hypotenuse

$cos(\theta) = \frac{-8}{17}$

By comparison

$Adj = -8\ and\ Hyp = 17$

Using Pythagoras

$Hyp^2 = Adj^2 + Opp^2$

By Substitution

$17^2 = (-8)^2 + Opp^2$

$289 = 64 + Opp^2$

Subtract 64 from both sides

$289 - 64 = 64 - 64 + Opp^2$

$225 = Opp^2$

Take square roots of both sides

$\sqrt{225} = \sqrt{Opp^2}$

$\sqrt{225} = Opp$

$15 = Opp$

$Opp = 15$

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

$Opp = -15$

From trigonometry

$Sin\theta = \frac{Opp}{Hyp}$

$Sin\theta = \frac{-15}{17}$

Also from trigonometry

$Tan\theta = Sin\theta / Cos\theta$

$Tan\theta = \frac{-15}{17} / \frac{-8}{17}$

$Tan\theta = \frac{-15}{17} * \frac{-17}{8}$

$Tan\theta = \frac{-15 * -17}{17 * 8}$

$Tan\theta = \frac{15 * 17}{17 * 8}$

$Tan\theta = \frac{15}{8}$

5 0

3 years ago