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3 years ago

Solve w^3=15 where w is a real number

Mathematics

1 answer:

lys-0071 [83]3 years ago

3 0

W =
$\sqrt[3]{15}$

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3 years ago

Which of the following is the quotient of b and a?

vlabodo [156]

$\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\
$

$\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
\\\\\\
\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}$

5 0

3 years ago

Find the value of x by filling in the blanks in the provided statement-reason solution. N = MP PLEASE HELP QUICKLYYY

seraphim [82]

Picture relating to the question can be found in the picture attached below.

Answer:

Angle DCA = Angle CAB

Angle A + Angle B + Angle C = 180°

18 + 3x + 3x = 180

27°

Step-by-step explanation:

For 1:

Angle DCA = Angle CAB (Alternate angles are equal)

Angle DCA = 18°, Hence, CAB = 18°

Angle A + Angle B + Angle C = 180° (sum of interior angles in a triangle)

3.)

Angle A = 18°

Angle B = 3x

Angle C = 3x

18° + 3x + 3x = 180°

4.)

18 + 3x + 3x = 180

18 + 6x = 180

6x = 180 - 18

6x = 162

x = 162 / 6

x = 27°

6 0

3 years ago