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tia_tia [17]
3 years ago
11

A pyramid shaped building is 873 ft tall with a square base that is 147 ft on each side. What is the volume of the​ pyramid?

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

V=6.28\times 10^6\ cm^3

Step-by-step explanation:

We have,

Height of pyramid shaped building, h = 873 ft

This pyramid consists of a square base that is 147 ft on each side.

It is required to find the volume of the​ pyramid. When the base of pyramid is square, its volume is given by :

V=\dfrac{1}{3}Bh\\

B is area of base, B=147\times 147=21609\ ft^2

i.e.

V=\dfrac{1}{3}\times 21609\times 873\\\\V=6288219\ ft^3

or

V=6.28\times 10^6\ cm^3

So, the volume of the pyramid is 6.28\times 10^6\ cm^3.

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Step-by-step explanation:

Box plot is enclosed.

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Minimum: 3.0

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Median: 7

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Absolute deviation: 30.5

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Answer:

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Step-by-step explanation:

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  • Domain = All reals

<h3>B. Range</h3>

The range is similar to the domain but is for y-values. So, the range is whatever y-values the graph applies to and crosses. As you can see from the graph, there are no y-values above 1. This means the range is y≤1.

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<h3>C. Increasing Interval</h3>

A graph is increasing when the y-values are increasing. So, on the parent function of a parabola, the graph increases to the right and decreases to the left. However, this graph is inverted and shifted to the left, so the interval will also be flipped and shifted. In this case, the graph increases from -∞ to 2.

  • Increasing Interval = [-∞, 2]

<h3>D. Decreasing Interval</h3>

The decreasing interval is very similar to the increasing interval. This interval applies when the y-values are decreasing as the x-values increase. For a parabola, the increasing and decreasing intervals always meet at the x-value of the vertex, which is 2 on this graph. The y-values decrease during the interval 2 to ∞.

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