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frutty [35]
4 years ago
9

Solve for the value of x. x - 3/5 = 4.71​

Mathematics
1 answer:
matrenka [14]4 years ago
6 0

Make 3/5 as a decimal = 0.60

x-0.60= 4.71

Move 0.60 to the other side. Sign changes from -0.60 to +0.60.

x-0.60+0.60= 4.71+0.60

x= 5.31

Answer : x= 5.31

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The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by
siniylev [52]

Answer:

the value of x=33

the measure of each base angle = 42 ,69,69

Step-by-step explanation:

Bases od isosceles triangles are congruent,so

2(2x+3)=4x+6 (This is the sum ob both anlgles base)

All angles in a triangle add to 180

4x+6 + 42 = 180

4x = 132

x=33

2(33)+3= 69

69+69+42 = 180

5 0
3 years ago
Read 2 more answers
The sum of 9 and twice a number
timofeeve [1]

Answer:

2x + 9

Step-by-step explanation:

Let, "A number", be denoted by the variable, x.

Note the meaning of each part:

"the sum" means addition, or + .

"twice" means multiply by 2

Put the parts together:

The sum of 9 and twice a number

2x + 9 is your amsw34.

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3 years ago
A bakery used 25% more butter this month than last month. If the bakery used 240 kilograms of butter last month, how much did it
yawa3891 [41]

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300kg

Step-by-step explanation:

4 0
3 years ago
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I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
Which of the following values best approximates the length of C in triangle ABC where C=
irinina [24]

Answer:

The correct answer is D 46.3644



8 0
3 years ago
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