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Brilliant_brown [7]
3 years ago
15

The question is: 5 < b - 3

Mathematics
2 answers:
Naily [24]3 years ago
6 0

Answer:

8 <b

Step-by-step explanation:

5 < b - 3

Add 3 to each side

5+3< b-3+3

8 <b

marishachu [46]3 years ago
3 0

Answer:

8 < b

Step-by-step explanation:

1. Add 3 by both sides to eliminate the -3 on b - 3.

2. You get 8 < b.

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Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

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First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

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Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


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