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Fynjy0 [20]
3 years ago
12

Given that 38 × 92 = 3,496, does 3.8 × 0.92 = 0.3496, 3.496, or 34.96?

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

3.496

Step-by-step explanation:

Multiply these two by getting rid of the decimal:

 38 -<em>decimal is moved one place here.</em>

<u>x092</u>  -<em>decimal is moved two places here.</em>

3496  -move decimal three places over.

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Two times a number minus six another number is six. Two times the first number added to three times the other number is twenty f
expeople1 [14]

Answer:

First Number: 2

Step-by-step explanation:

You need to work backwards, as an algebraic equation.

24 ÷ 3 = 8

8 ÷ 2 = 4

4 × 2 = 8

8 - 6 = 2

The first number is 2.

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2 years ago
Solve 5x4/9. help pleeeeaaassee
Rus_ich [418]

Answer:

\sf \: 2 \frac{2}{9}

Step-by-step explanation:

Q) 5 × (4/9) = ?

→ (5 × 4)/9

→ 20/9

\rightarrow\sf \: 2 \frac{2}{9}

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2 years ago
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Answer:

CD is equal to 3.2 m

Perimeter is equal to 37.5 m

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2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%7Bx%7D%5E%7B2%7Dy%20-%20%20%5Cfrac%7B8%7D%7B9%7Dx%20%7By%7D%5E%7B2
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3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
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