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3 years ago

What is the correct order of processes in the accretion of planetesimals?

Chemistry

2 answers:

forsale [732]3 years ago

6 0

Answer:

Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.

Explanation:

Planetesimals are the foundation or fundamentals of planet formation. The mode of the formation is called accretion. In this process, dust grains or particles mixes with atoms and molecules to form a massive mass which later coalesce or collide to form planets.

The size of the planet formed is determined by the amount of masses of matter that collide.

AURORKA [14]3 years ago

3 0

Answer: The answer is C: Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.

hope this helps you :)

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How does cellular respiration help humans

babunello [35]

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3 years ago

Read 2 more answers

Select all that apply. Which of the following bases are strong enough to deprotonate CH3CH2CH2Câ¡CH (pKa = 25), so that equilibr

Trava [24]

Answer:

b, c, and d.

Explanation:

In an acid-base reaction, the equilibrium favors the weaker acid, thus, to the reaction favors it, the product must be weaker than the acid given. As higher is the value of pKa, as weak is the acid. Thus, the base must form a conjugate acid with pKa > 25.

The values of pKa can be found in equilibrium tables. The salts will dissociate to form the acids, which will gain one proton (H+)

a. CH3ONa -> Conjugate acid CH3OH, pKa = 15.5

b. NaNH2 -> Conjugate acid NH3, pKa = 38

c. NaH -> Conjugate acid H2, pKa = 35

d. CH3CH2Li -> Conjugate acid CH3CH3, pKa = 50

e. H2O -> Conjugate acid H3O+, pKa = -1.7

f. NH3 -> Conjugate acid NH4+, pKa = 9.2

Thus, the ones with pKa > 25 are NH3, H2, and CH3CH3, thus the bases are NaNH2, NaH, and CH3CH2Li.

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3 years ago

Help will make brainliest! :)

Nataly_w [17]

Answer:

im not sure, but i believe its T. the dew point is 76.

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3 years ago

Boiling point of a solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water. kB= 0.512 c/m.

Nookie1986 [14]

100.133 degree celsius is the boiling point of the solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water.

Explanation:

Balanced eaquation for the reaction

CaCl2 + 2H20 ⇒ Ca(OH)2 + HCl

given:

mass of CaCl2 = 15.2 grams

mass of the solution = 57 grams

Kb (molal elevation constant) = 0.512 c/m

i = vont hoff factor is 1 as 1 mole of the substance is given as product.

Molality is calculated as:

molality = $\frac{grams of solute}{grams of solution}$

= $\frac{15.2}{57}$

= 0.26 M

Boiling point is calculated as:

ΔT = i x Kb x M

= 1 x 0.512 x 0.26

= 0.133 degrees

The boiling point of the solution will be:

100 degrees + 0.133 degrees (100 degrees is the boiling point of water)

= 100.133 degree celcius is the boiling point of mixture formed.

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3 years ago

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Answer:

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