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zhannawk [14.2K]
2 years ago
12

What is the correct order of processes in the accretion of planetesimals?

Chemistry
2 answers:
forsale [732]2 years ago
6 0

Answer:

Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.

Explanation:

Planetesimals are the foundation or fundamentals of planet formation. The mode of the formation is called accretion. In this process, dust grains or particles mixes with atoms and molecules to form a massive mass which later coalesce or collide to form planets.

The size of the planet formed is determined by the amount of masses of matter that collide.

AURORKA [14]2 years ago
3 0

Answer: The answer is C: Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.

hope this helps you :)

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Pls help! Polonium has a large, unstable nucleus. Through which process is it most likely to become stable?
Stella [2.4K]

The process through which Polonium is most likely to become stable is: B. alpha decay.

An unstable element refers to a chemical element that lose particles because its nucleus contain an excess of internal energy (neutron or proton).

This ultimately implies that, an unstable element is radioactive in nature.

In Science, some examples of an unstable element are:

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Polonium is a chemical element with a large, unstable nucleus.

Basically, the most stable isotope of Polonium is Polonium-209, which typically undergoes an alpha decay to form lead-205 and the emission of an alpha particle.

⇒  ^{209}_{84}Po ----> ^{205}_{82}Pb \;+\; ^{4}_{2}\alpha

In conclusion, we can deduce from the above chemical equation that Polonium is most likely to become stable through an alpha decay.

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saveliy_v [14]
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3 years ago
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A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure
Ostrovityanka [42]

The volume did not change, it remained at 20 ml

<h3>Further explanation</h3>

Given

20 ml a sample gas at STP(273 K, 1 atm)

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Required

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Solution

Combined gas Law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

\tt \dfrac{1\times 20}{273}=\dfrac{2\times V_2}{546}\\\\V_2=\dfrac{1\times 20\times 546}{273\times 2}\\\\V_2=20~ml

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2 years ago
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Answer:

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