Answer:
the area of the curve y= f(x) = x between x = 5 and x = 10
Step-by-step explanation:
- Finding the area of the curve y = f(x) = x between x = 5 and x = 10
Using the Area formula
As the area of curve lies between x = 5 and x = 10
so
so the integral expression becomes
![A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cfrac%7Bx%5E%7B1%2B1%7D%7D%7B1%2B1%7D%5Cright%5D%5E%7B10%7D_5)
![=\left[\frac{x^2}{2}\right]^{10}_5](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cright%5D%5E%7B10%7D_5)
![=\frac{1}{2}\left[10^2-5^2\right]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Cleft%5B10%5E2-5%5E2%5Cright%5D)
Therefore, area of the curve y= f(x) = x between x = 5 and x = 10
It is about $10
round $3.85 to $4
round $3.06 to $3
round $2.79 to $3
add them together $4+$3+$3=$10
Answer:
You should <u>carry 2 other batteries.</u>
Step-by-step explanation:
If the average life of each battery tends to last 6.9 months, and what you need is a year of battery supply, you probably need to carry two batteries.
The battery inside the flashlight has probably already spent much of its half-life.
We are told that the flashlight already has a battery inside, the batteries are discharged inside the flashlight even if the flashlight is not being used.
Which means that the average life of that battery is wearing out.
It would take 2 more batteries in addition to the one already inside the flashlight to supply the need for these for a year.
<span>P=2,500</span><span>females=f</span><span>males=f+<span>240</span></span>
Subtract 12 from both sides
4(2x + 2) > 100 - 12
Simplify 100 - 12 to 88
4(2x + 2) > 88
Divide both sides by 4
2x + 2 > 88/4
Simplify 88/4 to 22
2x + 2 > 22
Subtract 2 from both sides
2x > 22 - 2
Simplify 22 - 2 to 20
2x > 20
Divide both sides by 2
x > 20/2
Simplify 20/2 to 10
<u>x > 10</u>
