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3 years ago

PART A: APPLICATION (10 marks)

Mathematics

1 answer:

Lelu [443]3 years ago

7 0

Answer:

Jerry's weight is 36kg and tom's weight is 66kg

Step-by-step explanation:

According to the given condition:

Let,tom's weight =x

Jerry's weight=y

So,

X=2y-6 ---(1)

X+y=102-----(2)

Put value of x from eq 1 in 2

2y-6+y=102

3y-6=102

3y=102+6

3y=108

Y=108/3=36

Jerry's weight is 36.

Put value of y in eq 1

X= 2(36) -6

X=72-6

X=66

So, Tom's weight is 66kg

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The number of internet users in mexico between 2004 and 2008 can be modeled as u(t) = 8.02(1.17t) million users where t is the n

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Answer:

a) 1.479 Million

b) 36.9%

c) 13.668%

Step-by-step explanation:

The complete question is attached in the image below.

The number of internet users in Mexico between 2004 and 2008 is modelled by the following equation:

$u(t)=8.02(1.17)^{t}$

Where, u(t) is in millions and t is the number of years since 2004.

Part a) Rate of change of internet users between 2004 and 2006

The rate of change of a function is defined as:

$\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

We have to find the rate of change between 2004 and 2006. For 2004 t = 0, and for 2006, t = 2. So the rate of change for the given function will be:

$\frac{u(2)-u(0)}{2-0}\\\\ =\frac{8.02(1.17)^{2}-8.02(1.17)^{0}}{2}\\\\ =1.479$

Thus, the average rate of change in number of internet users in Mexico from between 2004 and 2006 was 1.479 million.

Part b) Percentage change of internet users between 2004 and 2006

The formula to calculate the percentage change is:

$\frac{\text{New value - Original Value}}{\text{Original Value}} \times 100\%$

Here, New value means the users in 2006 and original value means the users in 2004.

Using the values in this formula, we get:

$\frac{8.02(1.17)^{2}-8.02(1.17)^0}{8.02(1.17)^{0}} \times 100\%\\\\ =36.89\%$

Thus, the percentage change in the number of internet users between 2004 and 2006 was 36.89%

Part c) Percentage of internet users in 2008

For 2008, t would be equal to 4.

So, the number of internet users in Mexico in 2008 would be = $8.02(1.17)^{4}=15.02857542$ million = 15,028,575 (rounded to nearest integer)

Total population of Mexico in 2008 = 109,955,400

We have to calculate what percentage of Mexico population was Internet users in 2008. The formula for this would be:

$\frac{\text{Concerned Value}}{\text{Total Value}} \times 100\%$

Here, concerned value is the number of internet users and total value is the total population. Using the values in this formula we get:

$\frac{15028575}{109955400} \times 100\%\\\\=13.668\%$

Thus, 13.668% of the population was internet users in 2008 in Mexico.

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3 years ago

A 16-ounce bottle of orange juice says that it contains 200 milligrams of vitamin C, which is 250% of the daily recommended dosa

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80 milligrams is the amount of vitamin C that is considered to be 100% of the daily recommended requirement for adults.

<h3>What is the daily recommended dosage of vitamin C for adults? </h3>

Parameter

The amount of liquid included in the bottle is 16 ounces.
The vitamin C content of the bottle comes to a total of 200 milligrams.

Since the orange juice container that has a capacity of 16 ounces states that it has 200 milligrams of vitamin C, this means that it fulfills 250% of an adult's recommended daily requirement for vitamin C. Then, for one hundred percent of the daily allotment,

As a result, we are able to draw the conclusion that the amount of vitamin C that is considered to be 100% of the daily recommended requirement for people is 80 milligrams.