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olga nikolaevna [1]
3 years ago
11

What is the mode of this set of data? 1982 1988 1989 1994 1995 2005

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005
12345 [234]3 years ago
8 0
This set of data has no mode because it has no repeating numbers. Mode is <span>the value that occurs the most in a given set of data and since this data set has no repeating numbers, it has no mode. </span>
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H(x) = 1/3x - 1 if h (15)
dalvyx [7]

Answer:

(

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f

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5 0
3 years ago
Joelle spent 1 1/2 hours studying for her science test. Rileigh studied 3/4 for of Joelle‛s time. What fraction of an hour did R
ale4655 [162]

Answer: 1¹/₈ hours

Step-by-step explanation:

Joelle spent 1¹/₂ hours reading and Rileigh spent 3/4 of that time.

To find out how much time Rileigh spent, multiply the fractions but first convert the improper fraction to a proper fraction:

= 1¹/₂ = 3/2

= 3/2 * 3/4

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= 1¹/₈ hours

7 0
2 years ago
What is 1/3 + 1/2?.......
Virty [35]

Answer:

5/6

Step-by-step explanation:

1/3 + 1/2 = 5/6

3 0
3 years ago
Read 2 more answers
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
A company makes electronic gadgets. One out of every 50 gadgets is faulty, but the company doesn't know which ones are faulty un
Talja [164]

Answer:

Yes, the company can expect a profit in the long term

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In this question, we are to project if a company is expected to make a profit or loss given the information in the question.

Let’s use the scenario of 50 gadgets produced.

1 is expected to be faulty, while 49 is thus expected to work perfectly.

Now, on this 49 sold, there is an expectancy of $3 profit. Hence, this means that for a batch of 50 gadgets produced, the amount of expected profit will be 49 * 3 = $147

The amount that would be used to repair the faulty unit is $80. If we subtract this from the total expected profit, we have $147-$80 = $67

Hence, per 50 gadgets sold, a total of $67 in profit is to be expected

This means profit is expected in the long tey

6 0
3 years ago
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