1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanya [424]
3 years ago
14

The distance between two parks on a city map is 1.8 inches. The actual distance between the parks is 2 miles. In the same city,

the distance from the library to the post office is 0.8 mile. What is the distance to the nearest tenth of an inch between the library and the post office on the map?
0.7 inch

1.4 inches

4.4 inches

6.7 inches
Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

HI there!

The correct answer is A. 0.7 inches

The ratio of the map is 0.9 in = 1 mi, so 0.9 / 0.8 = 0.72 rounds to 0.7

Your friend, ASIAX

makkiz [27]3 years ago
7 0

First, find the scale of distance on the city map to actual distance.

1.8 / 2 = 0.9

Second, multiply to find the actual distance.

0.8 * 0.9 = 0.72

Third, round down.

0.72 → 0.7

Therefore, the answer is [ 0.7 inch ]

Best of Luck!

You might be interested in
Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minut
solmaris [256]

Answer:

6.11km/hr

Step-by-step explanation:

Let the speed that Kelli swims be represented by Y

Speed of the river = 5km/hr

Distance = Speed × Time

Kelli swam upstream for some distance in one hour

Swimming upstream takes a negative sign, hence:

1 hour ×( Y - 5) = Distance

Distance = Y - 5

She then swam downstream the same river for the same distance in only 6 minutes

Downstream takes a positive sign

Converting 6 minutes to hour =

60 minutes = 1 hour

6 minutes =

Cross Multiply

6/60 = 1/10 hour

Hence, Distance =

1/10 × (Y + 5)

= Y/10 + 1/2

Equating both equations we have:

Y - 5 = Y/10 + 1/2

Collect like terms

Y - Y/10 = 5 + 1/2

9Y/10 = 5 1/2

9Y/ 10 = 11/2

Cross Multiply

9Y × 2 = 10 × 11

18Y = 110

Y = 110/18

Y = 6.1111111111 km/hr

Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.

4 0
3 years ago
6. The table shows the equations Ms. Valez discussed in math class today.
k0ka [10]

Answer:

One zero is always added when the power is added by +1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In the ASA Congruence Postulate, the side between the angles is called the ___ side.
rusak2 [61]
No English plees enpanio
6 0
3 years ago
A man weighs 180 lb. He jogs a mile in 8 minutes. How many calories has he used up?
s2008m [1.1K]
Calories used = Activity level*Weight*Duration

Activity level at 8 min/mile = 0.22 calories per minute
Weight = 180/2.2 = 81.81 kg
Duration = 8 minutes

Substituting;
Calories used = 0.22*81.81*8 = 144 calories
8 0
3 years ago
63 40 51 70 36 21 51 28 19 find the mean of data
nikklg [1K]

Answer:

42.11

Step-by-step explanation:

Add all of the numbers, and then divide the total of the numbers by 9. With 9 being how many numbers are added.

5 0
3 years ago
Other questions:
  • Write the number as an improperios fraction, 10 3/4
    12·1 answer
  • Triniti had $500 in a savings account at the beginning of the summer. She withdraws $25 each week for food, clothes, and movie t
    8·1 answer
  • What is the value of x? A.86 B.60 C.52 D.26
    15·1 answer
  • F(x)=3x^2-36 find x
    8·1 answer
  • Mrs.suarez cut a pizza into 8 equal slices.each person in her family ate 2 slices .if there are 3 people in her family,what frac
    6·2 answers
  • Solve the right triangle. Round decimal answers to the nearest tenth.
    10·1 answer
  • Jane has earned a 91, 85, and 84 on her first three quizzes of the semester. If she hopes to have an A quiz average (90 or above
    5·1 answer
  • Please help me please
    10·1 answer
  • Find The Solution Set Of The Following
    13·1 answer
  • What comes next in this pattern? 7/2, 6/3, 5/4, ... 4/9 4/7 4/5
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!