<span>Starting position:
Let B start at origin(O) & A is at (-150 ,0) ie 150 km west of the origin . At 3pm , t= 0
A is changing its position at ( 150-35t) km/h
& B is changing its position at 25t km/h
Therefore
AB^2 = OA^2 + OB^2 /// Pythagoras Theorem
= (150-35t)^2 + ( 25t)^2
= 22 500 - 10 500 t + 1225t^2 +625t^2
= 22 500 - 10 500t + 1850t^2
AB = ( 22 500 - 10 500t + 1850t^2)^1/2
d (AB) /dt = 1/2 * ( 22 500 - 10 500t + 1850t^2)^-1/2 * ( - 10 500 + 3700t)
= ( - 5250 + 1850t) / ( 22 500 - 10 500t + 1850t^2)^1/2
At 3pm , t=0
At 7pm , t= 4
So d (AB) /dt = ( -5250 + 1850*4) / ( 22500 - 10500*4 + 1850*4^2)^1/2
= 2150 / 100.5
= 21.4 km/hr
</span>The distance between the ships changing at 7 P.M. is with a speed of 21.4 km/hr.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
<span>f<span>(<span>g<span>(x)</span></span>)</span></span>=<span>ln<span>(<span>ex</span>−1+1)</span></span>=<span>ln<span>(<span>ex</span>)</span></span>=x<span>ln<span>(e)</span></span>=<span>x</span>
Answer:
The answer would be 12.571428571 units or 12.57units.
3 5/4 x 11 = __
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I think it is the ASA theorem, but im like 70% sure.
we see two angles that are being compared in additon to the joined sides of the smaller triangle inside the larger one