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Mariana [72]
3 years ago
11

What does it mean for two fractions to be equivalent? For two ratios to be equivalent?

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

Equivalent fractions and ratios mean that when simplified, they are the same one fraction or ratio. see examples below.

Step-by-step explanation:

For example, the fraction 1/2 is the same as 2/4 or 15/30 because when you simplify them, they are still 1/2. Therefore they are equivalent.

For example, the ratio 1:2 is the same as 5:10 or 10:20 since when broken down they all come down to 1:2. Hence they are equivalent.

Hope this answers your question.

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The expression would be (X-6)/7
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The amount of blueberries picked, in pounds, varies directly as the number of hours worked. After
OverLord2011 [107]

Answer:

3

Step-by-step explanation:

3 pounds were picked per hour

4 0
3 years ago
Read 2 more answers
Last year, James earned £1,300 per month.
mrs_skeptik [129]

Answer:

1300/100 X 105 = 1365

1365/4 = 341.25 per week

341.25/40= 8.53125

$8.53

6 0
3 years ago
Can someone help me with number 10, 11, 12, 15, and 16 I don’t understand them thanks
yanalaym [24]

10)

10^2-48:6+25*3=100-8+75=167

11)

8(\frac{16}{4} )+2^2-11*3=32+4-33=3

12)

(\frac{6}{3} +4)^2:4*7=(2+4)^2:4*7=6^2:4*7=36:4*7=9*7=63

13) (your answer is incorrect)

5(9-4)^2-3^2=5*5^2-3^2=5*25-9=125-9=116

14) (your answer is incorrect)

5^2-2^2*4^2-12=25-4*16-12=25-64-12=-51

15)

(\frac{50}{5^2} )^2:4=(\frac{50}{25} )^2:4=2^2:4=4:4=1

16)

\frac{24+32+30+28}{2}-expression to represent this situation

\frac{24+32+30+28}{2}=\frac{114}{2}=57

Answer: In 1 group 57 students

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P.S. Hello from Russia :^)

4 0
2 years ago
the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
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tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
3 years ago
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