First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
<span>4, 8, 12, 16, 24, 48</span>
Answer:
0, 2/3
Step-by-step explanation:
Its the only one that make sense.
hope thats right
edge 2020
I couldn’t figure out d answer to This hope this helped
Answer:
<u>a. 11</u>
<u>b. 9</u>
Step-by-step explanation:
<em>A:</em>
2 x 4 = 8
8 + 3 = 11
<em>B:</em>
-2 x -2 = 4
4 + 5 = 9
Hope this helps! Let me know if it was right!