To answer this, let's first describe the two areas and obtain the pertinent dimensions from them.
The area of the square hole is 5 cm^2. Since A = s^2, where s is the length of a side of the square, s = +√5 in this situation. +√5 is approx. 2.24 cm.
The area of the round peg is 5 cm^2 also, but the area is calculated using a different formula: A = πr^2, where r is the radius of the circle. Solving for r^2, we get:
r^2 = A/π. Here, r^2 = (5 cm^2)/π = 5π, so that:
r = +√(5π). This is approx. 3.96 cm, and so the diameter is twice that, or 7.93 cm.
So there's plenty of room for the round peg to enter the square hole, but not the other way around!
Answer:
490
Step-by-step explanation:
Let us first count the handshakes between two gremlins. There are 20 gremlins, so there must be 20*19/2=190 handshakes between two gremlins, making sure to divide by two to avoid over-counting.
There are 15 imps that shake hands with each of the 20 gremlins, which makes 15* 20 = 300 handshakes between imps and gremlins.
Adding these up, you have $300 + 190 = 490 total handshakes.
Hope this helps!
Is this a graphing question or…
Answer:
116
Step-by-step explanation:
Total degrees in a pentagon: 540
Therefore, x + x + 100 + 101 + 107 = 540
2x + 308 = 540
2x = 232
x = 116
Answer:
A.
Step-by-step explanation:
as u can see,the other acute angle is 43° and the other is also an acute angle and acute angles must not surpass until 80° meaning, the other acute angle is 47°
