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SSSSS [86.1K]
2 years ago
9

HAAAALPPP PLEASEEEEEE NO LINKS ;(

Mathematics
1 answer:
Ad libitum [116K]2 years ago
3 0

Answer:

copy and paste your question into brainly

Welcome C;

Mark brainiest ez

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Natalka [10]
5.3/8=.6625 yrds^2 should be right
8 0
2 years ago
Calculate the length of the circumference of a circle with radius of 2.8cm
kykrilka [37]
Hello. D= 2×r D=2×2,8 D=5,6cm. Circumference= \pi × D ; C= 3,14×5,6 C=17,584cm. I hope to have helped you.

6 0
3 years ago
Read 2 more answers
Could someone answer this for me?​
MA_775_DIABLO [31]

Answer:

12 and 13 I believe

Step-by-step explanation:

12x12=144

13x13=169

4 0
3 years ago
Find a1, for the arithmetic series<br> with S14 = - 420 and d = -6.
faust18 [17]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} n = 14\\ d= -6 \end{cases} \\\\\\ a_{14}=a_1+(14-1)(-6)\implies a_{14}=a_1+(13)(-6)\implies a_{14}=a_1-78 \\\\[-0.35em] ~\dotfill

\bf \textit{sum of a finite arithmetic sequence} \\\\ S_n=\cfrac{n(a_1+a_n)}{2}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{last term's}\\ \qquad position\\ a_1=\textit{first term}\\ \cline{1-1} n= 14\\ S_{14}=-420\\ a_{14}=a_1-78 \end{cases}\implies S_{14}=\cfrac{n(a_1+a_{14})}{2} \\\\\\ -420=\cfrac{14[a_1+(a_1-78)]}{2}\implies -420=7(2a_1-78)\implies \cfrac{-420}{7}=2a_1-78 \\\\\\ -60=2a_1-78\implies 18=2a_1\implies \cfrac{18}{2}=a_1\implies 9=a_1

8 0
3 years ago
Kenji packed an exercise ball into a cylindrical package . How much space does the package occupy in terms of pi . Enter your an
grandymaker [24]

Answer:

The space that the package would occupy is 45\pi cubic feet.

Step-by-step explanation:

The space that the package occupies is the volume of the cylinder. The volume of an object is the 3 dimensional capacity of the object.

Volume of a cylinder = \pir^{2}h

where: r is the radius and h is the height of the cylinder.

Given that; h = 5 feet and r = 3 feet.

The required volume = \pi × (3)^{2} × 5

                                   = \pi  × 9 × 5

                                  = 45\pi cubic feet

The space that the package would occupy is 45\pi cubic feet.

3 0
3 years ago
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