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2 years ago

What is the answer to 4(x + 1) = -6

Mathematics

2 answers:

wariber [46]2 years ago

7 0

The answer is -5/2 because when u take 4 plus 1 equal 5 but since her negative u add negative

snow_tiger [21]2 years ago

3 0

Answer:

-5/2

Step-by-step explanation:

With Distributive property, we get 4x + 4 = -6. Subtract 4 from both sides and we get 4x = -10. Divide both sides by 4 and we get x = -5/2.

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Which table shows a proportional relationship?

Fittoniya [83]

Answer:

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2 years ago

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Mike and Kate plan to save money for their wedding over a 20 month period. They will need to save $8,000 to help pay for the wed

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-Answer:Option B: Increase the amount of money they save each month by $80 from what they've been saving.

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1 year ago

(FIRST CORRECT FOR BRAINIEST) Solve for x

Katyanochek1 [597]

Answer:

x = 12

Step-by-step explanation:

Angles in a triangle add up to equal 180 degrees

Hence, 10x - 11 + 3x - 2 + 3x + 1 = 180

( note that we just created an equation that we can use to solve for x )

we now solve for x using the equation we created

10x - 11 + 3x - 2 + 3x + 1 = 180

step 1 combine like terms

10 + 3x + 3x = 16x

- 11 - 2 + 1 = -12

we now have 180 = 16x - 12

step 2 add 12 to each side

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180 + 12 = 192

we now have 192 = 16x

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16x / 16 = x

192 / 16 = 12

we're left with x = 12

4 0

3 years ago

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The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

2 years ago

I got 77 for my total answer. I correct? if not can some help

mote1985 [20]

Yes you got it correct.

8 0

3 years ago

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