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Korvikt [17]
3 years ago
8

11) (-2x) (-1 + 9x) - 4x (4 + 5x)12) 3 (-5x - 3) + 4 (6 - 3x)

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

11) -14x-38x2 (squared)

12) 27x+15

Step-by-step explanation:

1. distribute the negative 2, distribute the negative 4, combine like terms

2. distribute the 3 to the parenthesis and distribute the 4 as well then combine like terms

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Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

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Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

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Cancel power on both side then we get

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Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

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Answered by GAUTHMATH

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