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4 years ago

Hellppppp I`ll give brainliest!

Mathematics

2 answers:

Alina [70]4 years ago

7 0

Answer:

B 20.60

Step-by-step explanation:

100/20=5

25.75/5= 5.15

25.75-5.15= 20.6

=20.60

Rus_ich [418]4 years ago

6 0

Answer: $20.60

Step-by-step explanation:

25.75×.2 = 5.15

$5.15 is how much they took off the total price.

$25.75 - $5.15 = $20.60

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The sum of three consecutive integers is 9.

strojnjashka [21]

Answer:

Step-by-step explanation:

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3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Slav-nsk [51]

Answer:

walnut park

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The running back for the Bulldogs football team carried the ball 9 times for a total loss of 20

Ivahew [28]

Yeah the answer is 16.

And could I get brainiest because I need to get it one more time to get to my next rank

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3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

At the book fair, Vald spends all of his money on new books. Pamela spends

Shkiper50 [21]

Step-by-step explanation:

Lets take Vald spends $100 on the book fair which are all the money he had.

Pamela Spends 2/3 as much as Vald

Pamela Spends 2/3 x 100 = $66.67

Eli Spends 4/3 as much as Vald

Eli spends 4/3 x 100 = $133.33

From here, we can see Eli Spends the most and Pamela Spends the least.

6 0

3 years ago