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3 years ago

Can someone please help me with these two questions

Mathematics

1 answer:

Anarel [89]3 years ago

4 0

Answer:

23. 0.4583 seconds

24. 0.0107 seconds

Step-by-step explanation:

The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.

90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s

23. The time it takes for the ball to travel 60.5 ft is ...

time = distance/speed

time = (60.5 ft)/(132 ft/s) = 0.4583 s

It takes 458.3 milliseconds to reach home plate.

24. time = distance/speed

time = (17 in)/(1584 in/s) = 0.0107 s

The ball is in the strike zone for 10.7 milliseconds.

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What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

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2 years ago

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2 years ago

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Kruka [31]

Answer:

1/14:5/7:3/14

Step-by-step explanation:

Since orange=15

Apple=5

Coconut milk=50

50+15+5

Orange=15/70

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=3/14

Apple=5/70

Divide both by 5

=1/14

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Divide both by 10

=5/7

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1/14:5/7:3/14

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2 years ago

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hram777 [196]

Answer:

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Step-by-step explanation:

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2 years ago

Triangle ABC has A(-3,6),B(2,1), and C(9,5) what the length of side AB? What the length BC what the length AC and what ABC

vovikov84 [41]

Answer:

AB = 5√2

AC = √145

BC = √65

Step-by-step explanation:

Using the formula for calculating the distance between two points

D = √(x2-x1)²+(y2-y1)²

For AB A(-3,6),B(2,1),

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AB = √(5)²+(-5)²

AB = √25+25

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For AC A(-3,6) and C(9,5)

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AC = √(12)²+(-1)²

AC = √144+1

AC = √145

For BC B(2,1), and C(9,5)

BC = √(9-2)²+(5-1)²

BC = √(7)²+(4)²

BC = √49+16

BC = √65

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8 0

2 years ago

Can someone please help me with these two questions ​

Can someone please help me with these two questions