All categories

3 years ago

Please help with these math problems thank you

Mathematics

1 answer:

makvit [3.9K]3 years ago

6 0

x/7 + x/7 =4

Calculate the sum

2/7x=4

multiply both sides of the equation by 7/2

x=14

b. 2x/3 - x/3 =4

Multiply both sides of the equation by 3

2x-x=12

collect like terms

x=12

c. 4x/5 - 2x/5 =7

Multiply both sides of the equation by 5

4x-2x=35

Collect like terms

2x=35

Divide both sides of the equation by 2

x= 35/2

d. x/6 + x/4 =3

Multiply both sides of the equation by 12

2x+3x=36

Collect like terms

5x=36

Divide both sides by five

x = 36/5

e. -x/-5 + x/4 =2

Multiply both sides by 20

-4x+5x=40

Collect like terms

x=40

f. x/3 - x/6 = 5

Multiply both sides by six

2x-x=30

Collect like terms

x=30

hope this helps!!

~lyndee

You might be interested in

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

Yo can someone help me out, I know the volume but which units again?

Jet001 [13]

meters cube or m³

Volume uses '³' or cube units on 3d models.

Area uses '²' or square units on 2d models.

6 0

3 years ago

Let f(x) = x^2 + 2x and g(x)= 3 – x. Find f(-3) + g(-3).

Ksenya-84 [330]

Answer:

g(x)=6 and f(x)=3 these are your answers for this equation

7 0

2 years ago

Frank purchased an air cooler for $3,000 in the year 2000. Its value depreciates by 8% each year. What is the value of the air c

Olenka [21]

Answer:

Step-by-step explanation:

<h2>Mark me brainliest please</h2>

4 0

3 years ago

Help me get the answer

drek231 [11]

This is hard- DHJDHSJS

3 0

3 years ago