Explanation:
First, let's rewrite the equation here:
4 NH3 + 6 NO -> 5 N2 + 6 H2O.
The equation tells us that 6 moles of NO produces 5 moles of N2.
But the question wants us to find the quantity in grams of NO required if we have 121 g of N2.
1. So first, let's transform 121 g of N2 into moles, using its molar mass (28 g/mol) and the following formula: moles = mass/molar mass
2. Then, we use the equation ratio between NO and N2: 6:5.
3. Then we transform the result into grams of NO, using its molar mass (30.01 g/mol) and the following formula: mass = moles*molar mass
1. moles = 121/28
moles = 4.3 moles of N2
2. 6 moles of NO --- 5 moles of N2
x moles of NO --- 4.3 moles of N2
5x = 4.3*6
x = 25.9/5
x = 5.2 moles of NO
3. mass = 5.2*30.01
mass = 155.6 g
Answer: It will require 155.6 g of NO.
(4) 220Fr, known as Francium-220, undergoes alpha decay, which emits an alpha particle, also known as a helium nucleus, which has a charge of +2.
I would say C. (2,3). If you input the values into the equation, it works out. If you put 2 in as x and y as 3, it’s 2 + 1 = 3 which obviously works. Also, if you plot the point (2,3) on the graph, the line intersects it.
Answer: 9.55 moles
Explanation: Moles are the base unit of atoms, molecules, ions, or any other substance. It is exactly 6.022 × 10²³ entities of any substance. The mole is equal to the ratio of the given mass to the molar mass.
Hope this helps :) If possible give brainliest
Answer:
Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula
Explanation:
This is the reaction:
NH₃ + H₃PO₄ → 28.2% N, 20.8% P, 8.1% H, 42.9% O
In 100 g of compound we have:
28.2 g N
20.8 g of P
8.1 g of H
42.9 g of O
Now we divide each between the molar mass:
28.2 g / 14 g/mol = 2.01 mol
20.8 g / 30.97 g/mol = 0.671 mol
8.1 g / 1 g/mol = 8.1 mol
42.9 g / 16 g/mol = 2.68 mol
And we divide again between the lowest value of moles
2.01 mol / 0.671 mol → 3
0.671 mol / 0.671 mol → 1
8.1 mol / 0.671 mol → 12
2.68 mol / 0.671 mol → 4
Molecular formula will be: N₃PH₁₂O₄ → (NH₄)₃PO₄
Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula
