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nikdorinn [45]
3 years ago
9

A strong acid, HA, is added to water. Which statement about the solution is true?

Chemistry
2 answers:
Akimi4 [234]3 years ago
5 0

Answer:

The correct answer is:It contains little or no HA.

Explanation:

When a strong acid is added to water it dissociates into its constituent ion .

HA+H_2O\rightarrow H_3O^++A^-

Actually the concentration of H^+ ions in water increases in comparison to hydroxide ions. And very little amount of HA will remain present associated in the solution.

natita [175]3 years ago
3 0
It contains mostly hydroxide ions
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What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
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<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

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