Find a point-slope form for the line with slope 1/5 and passing through the point (-7,-4).
1 answer:
Answer:
y + 4 = ⅕(x + 7)
Step-by-step explanation:
The "point-slope" form of the equation of a straight line is:
y − y₁ = m(x − x₁)
where m is the slope and (x₁, y₁) is a point on the line.
If m = ⅕ and (x₁, y₁) = (-7, - 4), the point-slope equation is
y + 4 = ⅕(x + 7)
The Figure below shows the graph of your line and a point at (-7, -4).
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Based on the docx you showed me, the equation for the parabola is 
and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).
If you use these two points to create a line we get the equation:
(I just used point slope form)
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
and the x-intercept: 
.
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
If you use these two points to create a line we get the equation:
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0