Answer:
1. 50 m
2. 80 cm
Step-by-step explanation:
1. There are 2 triangles, subtract the area of 1 of them from the other.
The triangle that needs to be subtracted: b = 20 m, h = 10 m
A = 1/2b * h = 1/2(20) * 10 = 10*10 = 100 m
The big triangle, the one that needs to be subtracted plus the one you need to find the area of: b = 20 cm, h = 15 cm, 1/2(20) * 15 = 10 * 15 = 150
150 - 100 = 50 c
2. Divide it into 3 parts:
1- 3*4 = 12
2. 7*(4 + 4) = 7*8 = 56
3. [(4 + 4) * (13 - 7 - 3)]/2 = (8*3)/2 = 24/2 = 12
12 + 56 + 12 = 80 cm
A word to the wise: It's <span> f(x)=125(0.9)^x, where ^ represents exponentiation.
In this case the ave. value over the interval [11, 15] is
125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
15 - 11 = (31.25) [ 0.2059 - 0.3138 ] = a negative result
= (31.25)(-0.1079) = -3.372 (av. r. of c.
over the interval [11,15] )
Do the same thing for the time interval [1,5]. Then compare the two rates of change.</span>
Answer:
One tailed
To conclude if there is an increase in the mean gas mileage due to new type of tire.
Step-by-step explanation:
We are given the following in the question:
The manufacture wants to compare increase in the mean gas mileage.
Population mean = 32 miles per gallon
Thus, the manufacture could carry a hypothesis test to compare mean.
A one tailed test (z-test or t-test) based on the information can be used to compare the increase in mean.
Thus,
The automotive manufacturer should perform a one tailed hypothesis test to conclude if there is an increase in the mean gas mileage due to new type of tire.
Answer:
Step-by-step explanation:
d=(10-3)^2+(8-8)^2=(7)^2+(0)^2=49
since it is in radical the the answer is 7
Answer:
113
Step-by-step explanation:
Let the number of adult tickets sold =a
Let the number of student tickets sold =s
A total of 259 tickets were sold, therefore:
a+s=259
Adult tickets were sold for $24 each and student tickets were sold for $16 each.
Total Revenue = $5,312
Therefore:
24a+16s=5,312
We solve the two derived equations simultaneously.
From the first equation
a=259-s
Substitute a=259-s into 24a+16s=5,312
24(259-s)+16s=5,312
6216-24s+16s=5,312
-8s=5,312-6216
-8s=-904
Divide both sides by -8
s=113
Therefore, 113 student tickets were sold.