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Genrish500 [490]
3 years ago
6

Will give brainlest!!GIVE THE HORIZONTAL ASYMPTOTE (Y = ?) THE DOMAIN

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0

Answer: i think 2

Step-by-step explanation:

You might be interested in
Substitution property of equality if y=-5 and 7x+y=11, then____. A. 7(-5) + y=11 B.7x-5=11 C.7x+5=11 D.-5+y=11
jolli1 [7]
7x+y=11 where y= -5                                                                                              So, when we substitute y in the equation then,
7x + (-5) = 11 that is 7x - 5 = 11....
So, B. is the right answer.

3 0
3 years ago
I need the answer with work
Alenkasestr [34]
1. Regroup terms
x^3 - 6 * 10x^2x-8/ x-3
2. Use product rule
x^3 - 6 * 10x^ 2+1 - 8/ x-3
3. Simplify
x^3 - 6 * 10 x^3 - 8/ x-3
4. Simplify further
x^3 - 60x^3 - 8/ x-3
5. Simplify the last time
-59x^3-8/x-3
3 0
3 years ago
The first term in the expansion of the binomial (3x + y)4
Lelechka [254]
I don't know if i'm right or what because I haven't learned binomial in like almost 4 years. (3x+y)?
5 0
3 years ago
Read 2 more answers
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
How many 9/16 foot pieces of wood can u cut from a board that is 3 15/16 feet long?
Ann [662]
Convert this to inches to find your answer.
Or what is a 1/16 of a foot in inches?
7 0
3 years ago
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