Given f(x)= 8x^{15}+6x^{8}-3x^{3}+5x^{2}, the degree is
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Answer:
16.5 units
Step-by-step explanation:
The midsegment is the distance between the midpoints of the nonparallel sides of the trapezoid.
The trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10).
We want to find the midsegment of ABCD to the nearest tenth.
The midpoint of BC is;
The midpoint of AD is :
The length of the midsegment is the distance from (-6,2) to (10.5,2)
% means out of 100 so If its 6% that = .06 then just multiply
