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3 years ago

Y + 2 =1/2(x – 3). Please help ?!?

Mathematics

1 answer:

Sidana [21]3 years ago

6 0

first, spread the parenthesis. y+2=1/2x-1.5

second, add 1.5 to both sides. y+3.5=1/2x

third, multiply by 2. 2y+7=x

if you are solving for y, do not do the third step, instead, subtract by 3.5. y=x-3.5

hope this helps!

ANSWER: x=2y+7 or y=x-3.5

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What is the equation of the line that passes through the point (8,1) and has a slope of 3/4

iris [78.8K]

Answer:

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$y = \frac{3}{4} x - 5$

Step-by-step explanation:

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3 0

3 years ago

6(m-1) = 3(3m + 2) Show all work

nordsb [41]

Answer:

$\boxed{\sf m = -4}$

Step-by-step explanation:

$\sf Solve \: for \: m: \\ \sf \implies 6 (m - 1) = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \sf \implies 6 m - 6 = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: right \: hand \: side: \\ \sf \implies 6 m - 6 = 9 m + 6 \\ \\ \sf Subtract \: 9 m \: from \: both \: sides: \\ \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\ \\ \sf 6 m - 9 m = -3 m: \\ \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\ \\ \sf 9 m - 9 m = 0: \\ \sf \implies -3 m - 6 = 6 \\ \\ \sf Add \: 6 \: to \: both \: sides: \\ \sf \implies (6 - 6) - 3 m = 6 + 6 \\ \\ \sf 6 - 6 = 0: \\ \sf \implies -3 m = 6 + 6 \\ \\ \sf 6 + 6 = 12: \\ \sf \implies -3 m = 12 \\ \\ \sf Divide \: both \: sides \: of \: -3 m = 12 \: by \: -3: \\ \sf \implies \frac{ - 3m}{ - 3} = \frac{12}{ - 3} \\ \\ \sf \frac{ - 3}{ - 3} = 1: \\ \sf \implies m = \frac{12}{ - 3} \\ \\ \sf - \frac{12}{3} = - 4 : \\ \sf \implies m = - 4$

7 0

3 years ago

1. How many variables are involved in the chi-square test?

GarryVolchara [31]

The result of the respective questions are:

This chi-square test only takes into consideration one variable.
The type of chi-square test this is is a Goodness of Fit
df= 3
NO

<h3>How many variables are involved in the chi-square test?</h3>

This chi-square test only takes into consideration one variable.

The type of chi-square test this is, is a Goodness of Fit

To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.

The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.

Parameter

n = 4

Therefore

Degrees of freedom

df= n - 1

df= 4 - 1

df= 3

In conclusion

Parameters

$\alpha = 0.05$

df = 3

Hence

Critical value = 7.814728

Test statistic = 6.6

Test statistic < Critical value, .

NO, the result of this test is not statistically significant.