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nirvana33 [79]
3 years ago
12

2x^{2} +4x+1=0 Solve for x.

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0
2x^2 + 4x + 1 = 0

2x^2 + 4x + 1 - 1 = 0 - 1

2x^2 + 4x = -1

X(2x + 4) = -1

X = -1.

2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.

I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
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