All categories

3 years ago

Which relation is a function?

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

Step-by-step explanation:

if you don't have from same x different outcomes is a function

think that x is a day you count votes, you can not get for the same day different y number of votes ( something is fishy then)

A. not a function because (6, -3) and (6, 3)

B. not a function because (4,7) and (4,2)

C. is a function

D. not a function because (2, -1) (2,1) (2,3)

You might be interested in

`h(t)=-5t^{2}+10t+3`

Ipatiy [6.2K]

Solve the equation for
t
t
by finding
a
a
,
b
b
, and
c
c
of the quadratic then applying the quadratic formula.
t
=
10
−
h
+
√
h
2
−
20
h
+
160
10
t
=
10
-
h
+
h
2
-
20
h
+
160
10
t
=
10
−
h
−
√
h
2
−
20
h
+
160
10

8 0

3 years ago

PLEASE HELP ME FAST!!!

yawa3891 [41]

Answer:

ans -------8/5 pansnhshshsh

6 0

3 years ago

Read 2 more answers

Business people have determined that three fourths of the items on a mailing list will change in one year. A business has a mail

Aliun [14]

1695 will be incorrect.

4 0

3 years ago

I need help converting 19/4 into a decimal.

kykrilka [37]

Answer:

4.75!

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$

8 0

3 years ago

Read 2 more answers