See the attached figure.
<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325
Answer:
16
Step-by-step explanation:
DE is the vertical line x=1. It extends between y=2 and y=7, a distance of 5 units.
EF is the horizontal line y=7. It extends from x=1 to x=4, a distance of 3 units.
Then the perimeter of half the rectangle is 5+3 = 8 units.
The perimeter of the rectangle is 2·8 = 16 units.
Answer:
The two linear equations are the same line
Step-by-step explanation:
two different linear equations can only possibly intersect at one point. once the two lines intersect, they cannot curve back to intersect once again.
The slope can sometimes be called the gradient, and the equation for the gradient is (y2 - y1)/(x2 - x1). So therefore, you'd do: (-8 - 7)/(4 - -5) which is (-15)/9) which is -1 2/3 or -1.6 (recurring), which is your answer. I hope this helps! Let me know if I've confused you :)
<span>the question is, If m∠D = 18° and m∠C = 45° what is arc BC? your answer is B. 54 degrees </span>