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BabaBlast [244]
2 years ago
12

50

Mathematics
1 answer:
ozzi2 years ago
7 0

Answer:

90 km, N 46° E

Step-by-step explanation:

<em>A jet flies due North for a distance of 50 km and then on a bearing of N 70° E for a further 60 km. Find the distance and bearing of the jet from its starting point.</em>

Look at the diagram I drew of this scenario. You can see the jet flies North for 50 km, and then turns at a 70° angle to fly another 60 km. We want to find the distance from the starting point, SP, to angle C (labeled).

This will be the jet's distance from its starting point.

In order to find the bearing of the jet from its starting point, we will need to find the angle formed between distances b and c, labeled angle A.

The <u>Law of Cosines</u> will allow us to use two known sides and one known angle to solve for the sides opposite of the known angle.

In this case, the known angle is 110° (angle B) so we will use the <u>Law of Cosines</u> respective to B.

  • b² = a² + c² - 2ac cosB

Substitute the known values into the equation and solve for b, the distance from the starting point (A) to the endpoint (C).

  • b² = (60)² + (50)² - 2(60)(50) cos(110°)
  • b² = 6100 -(-2052.12086)
  • b² = 8152.12086
  • b = 90.28909602
  • b ≈ 90 km

The distance of the jet from its starting point is 90 km. Now we can use this b value in order to calculate angle A, the bearing of the jet.

The <u>Law of Cosines</u> with respect to A:

  • a² = b² + c² - 2bc cosA

Substitute the known values into the equation and solve for A, the bearing from the starting point (clockwise of North).

  • (60)² = (90.28909602)² + (50)² - 2(90.28909602)(50) cosA
  • 3600 = 8152.12086 - 6528.909602 cosA
  • -4552.12086 = -6528.909602 cosA
  • 0.6972252853 = cosA
  • A = cos⁻¹(0.6972252853)
  • A = 45.79519
  • A ≈ 46°

The bearing of the jet from its starting point is N 46° E. This means that it is facing northeast at an angle of 46° clockwise from the North.

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Step-by-step explanation:

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There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther
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There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

\frac{2}{n}=\frac{3}{d}...(1) or

n=\frac{2d}{3}...(1)

For every 2 dimes there are 5 quarters. We can represent this information in an equation as:

\frac{2}{d}=\frac{5}{q}...(2) or  

q=\frac{5d}{2}...(2)  

There are 500 coins total. We can represent this information in an equation as:

n+d+q=500...(3)

We will use substitution method to solve our given system.

Upon substituting equation (1) and equation (2) in equation (3), we will get:

\frac{2d}{3}+d+\frac{5d}{2}=500  

Multiply the equation by 6:

\frac{2d}{3}*6+d*6+\frac{5d}{2}*6=500*6  

2d*2+6d+5d*3=3000  

4d+6d+15d=3000  

25d=3000  

\frac{25d}{25}=\frac{3000}{25}  

d=120  

Therefore, there are 120 dimes in the piggy bank.

Upon substituting d=120 in equation (1), we will get:

n=\frac{2(120)}{3}

n=2(40)

n=80

Therefore, there are 80 nickels in the piggy bank.

Upon substituting d=120 in equation (2), we will get:

q=\frac{5d}{2}  

q=\frac{5(120)}{2}  

q=5(60)  

q=300  

Therefore, there are 300 quarters in the piggy bank.

Now, we need to find the value of all coins.

We know 1 quarter is worth $0.25, so 300 quarters will be worth \$0.25\times 300=\$75.

We know 1 dime is worth $0.10, so 120 dimes will be worth \$0.10\times 120=\$12.

We know 1 nickel is worth $0.05, so 80 nickels will be worth \$0.05\times 80=\$4.

\text{All coins worth}=\$75+\$12+\$4

\text{All coins worth}=\$91

Therefore, all coins in the piggy bank worth $91.

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