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3 years ago

Please help! I will give 50 points and brainliest.

Mathematics

1 answer:

QveST [7]3 years ago

8 0

Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

x³+3x²+x²-4x+12x-16

x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

So the domain is just all real numbers without -4

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3 years ago

If i=√-1 , what is i^2 equal to ?

Alja [10]

Answer:

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3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$