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lukranit [14]
4 years ago
14

Samantha spent 40 minutes on homework. Sixty percent of that time was spent on language arts.how many minutes were spent on lang

uage arts?
Mathematics
2 answers:
yan [13]4 years ago
3 0
If you would like to know how many minutes were spent on language arts, you can calculate this using the following steps:

60% of 40 minutes = 60% * 40 = 60/100 * 40 = 24 minutes

The correct result would be: 24 minutes were spent on language arts.
aksik [14]4 years ago
3 0

Answer:

24 MINUTES

Step-by-step explanation:

AYEEEEEEEEEEE....

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in a shipment of 50 calculators, 4 are defective. one calculator is randomly selected and tested. what is the probability that i
Serga [27]
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3 0
3 years ago
Find the complete time-domain solution y(t) for the rational algebraic output transform Y(s):_________
bija089 [108]

Answer:

y(t)= 11/3 e^(-t) - 5/2 e^(-2t) -1/6 e^(-4t)

Step-by-step explanation:

Y(s)=\frac{s+3}{(s^2+3s+2)(s+4)} + \frac{s+3}{s^2+3s+2} +\frac{1}{s^2+3s+2}

We know that s^2+3s+2=(s+1)(s+2), so we have

Y(s)=\frac{s+3+(s+3)(s+4)+s+4}{(s+1)(s+2)(s+4)}

By using the method of partial fraction we have:

Y(s)=\frac{11}{3(s+1)} - \frac{5}{2(s+2)} -\frac{1}{6(s+4)}

Now we have:

y(t)=L^{-1}[Y(s)](t)

Using linearity of inverse transform we get:

y(t)=L^{-1}[\frac{11}{3(s+1)}](t) -L^{-1}[\frac{5}{2(s+2)}](t) -L^{-1}[\frac{1}{6(s+4)}](t)

Using the inverse transforms

L^{-1}[c\frac{1}{s-a}]=ce^{at}

we have:

y(t)=11/3 e^{-t} - 5/2 e^{-2t} -1/6 e^(-4t)

6 0
4 years ago
I added a picture : Determine which of the lines, if any, are parallel or perpendicular. Explain.
exis [7]

Answer:

1. line a and c and parallel. line b is perpendicular with line a and c. 2. line b and c and parallel. line a is perpendicular to lines b and c. 3. y= -3x + 3 4. y=(5/3)x - 9

Step-by-step explanation:

To find parallel and perpendicular, make the slope opposite and find b by plugging in the points. Parallel is the same slope.

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