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brilliants [131]
3 years ago
6

the area of a square is A = s^2, where s is the length of one side of the square. what is the side length s for each square ? th

e square with A = 324in^2
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

18

Step-by-step explanation:

324 = s^2 -->

sqrt324 = s -->

sqrt(2^2 * 9^2) = s -->

2*9 = s -->

18 = s

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three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
goldenfox [79]
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure

6 0
3 years ago
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(a−2b)3 when a=−4 and b=−1/2
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Answer:

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Step-by-step explanation:

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3 0
2 years ago
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Step-by-step explanation:

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